5.3.2. Theorem 5.1.

If some row of A is the zero vector, then detA=0 .

Proof

Let A k =O .  Since t A k =O= A k , we have, with t=1 ,

        d( , A k , )=d( , A k , )

However, by axiom 1, we have

        d( , A k , )=d( , A k , )

Hence,

        d( , A k , )=d( , A k , )=0

QED.